16[x+3]=4[4x+5]+28

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Solution for 16[x+3]=4[4x+5]+28 equation:


Simplifying
16[x + 3] = 4[4x + 5] + 28

Reorder the terms:
16[3 + x] = 4[4x + 5] + 28
[3 * 16 + x * 16] = 4[4x + 5] + 28
[48 + 16x] = 4[4x + 5] + 28

Reorder the terms:
48 + 16x = 4[5 + 4x] + 28
48 + 16x = [5 * 4 + 4x * 4] + 28
48 + 16x = [20 + 16x] + 28

Reorder the terms:
48 + 16x = 20 + 28 + 16x

Combine like terms: 20 + 28 = 48
48 + 16x = 48 + 16x

Add '-48' to each side of the equation.
48 + -48 + 16x = 48 + -48 + 16x

Combine like terms: 48 + -48 = 0
0 + 16x = 48 + -48 + 16x
16x = 48 + -48 + 16x

Combine like terms: 48 + -48 = 0
16x = 0 + 16x
16x = 16x

Add '-16x' to each side of the equation.
16x + -16x = 16x + -16x

Combine like terms: 16x + -16x = 0
0 = 16x + -16x

Combine like terms: 16x + -16x = 0
0 = 0

Solving
0 = 0

Couldn't find a variable to solve for.

This equation is an identity, all real numbers are solutions.

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